THE TEMPLE OF METROLOGY
Figure 1, The Great Pyramid and Temple (model).
On the east side of the Great Pyramid is the Temple of metrology with its basalt base, a rectangular building measuring about 171 feet from north to south and about 132 feet from east to west. Patches of the black basalt paved courtyard remain along with the sockets which held huge fifty granite pillars that formed a colonnade around the courtyard. From the Temple a causeway leads off in a straight line at an angle 14Âº North of due East:
Figure 2, The Temple of metrology
Basalt base (pavement) = basalt!?
Why was basalt used?
Basalt =
lava
The answer is here: when basaltic lava cools, it shrinks. In thick sheets of basaltic lava, this shrinking can produce shrinkage cracks that often occur in a
hexagonal pattern and create
hexagonal columns of rock, a process known as columnar jointing:
Figure 3, Basalt hexagonal patterns, Devils Postpile National Monument, California
Figure 4, Hexagon
Temple = 50 pillars (Figure 2)
Base of the Great Pyramid (four sides) = 927.71468 meters:
927.71468 : 50 =
18.5542936m = 1/100 of one minute (1') of Longitude.
Angle of the Temple's causeway =
14Âº
Tangent 14Âº = 0.249328002
(927.71468 : 2) : 0.249328002 = 1860.430181 m
1860.430181 : 4 = 465.1075454 =
AB (Figure 6)
Hexagon = 6 triangles
1 triangle = 3 sides
6 triangles =
18 sides
465.1075454 : 18 =
25.83930808 =
r (Figure 4) = radius of the circle
A (Figure 5).
Figure 5
Figure 5:
Radius of the circle A = 25.83930808 m
Area of the circle
A = 2097.544899 mÂ² = area of the square B = 45.79896176Â² = 52.12661939 x 40.23941939 m =
171.0190925 x 132.0190925 feet =
dimensions of the Temple of metrology.
Figure 6, April 27: ephemeris of the Sun +14Âº
Figure 6:
β = causeway's angle =
14Âº
AB = 465.1075454 m
BC = 115.964335 m = 1/2 of the Pyramid's base = position of the Temple =
C.
April 26-28th*:
ephemeris of the Sun =
+14Âº
Gregorian calendar:
April 27th = 116.2602377th day of a year = diameter of a year:
Figure 7, Diameter of the circle A = 116.2602377 days
Figure 7:
Circle
A (circumference) = 365.242 days = 1 year
Diameter of the circle
A =
116.2602377 days
Area of the circle
A = area of the square
B
Every side of the square
B =
103.0329095 days
April 27 of the Gregorian calendar is April 14 of the Julian calendar = 103.0329095-th day of a year.
Figure 8, Diameter of the circle = 103.0329095 days
Figure 8:
d = 103.0329095 days
Area of the circle = area of the square
AB = 91.3105 days =
BC =
CD =
DA = Seasons
Figure 9
Figure 9:
Radius (
r) of the circle
B =
103.0329095 days (1/2 of the King's Chamber width = 103.0329095 inches).
Area of the circle
B = 33,350.42967 days = area of the square
A
One side of the square
A = 182.621 "days" = 1/2 of a year
Angle
β = 32.48165854Âº = north "air-channel" of the King's Chamber (ascend).
Tangent 32.48165854Âº = 0.63662031:
103.0329095 x 0.63662031 =
65.59284278 days = radius of the circle
C:
(2 x 65.59284278) x 3.14159 =
412.131638 days = circumference of the circle
C = length of the King's Chamber (in inches).
412.131638 days = 1.128379644 years:
1.128379644Â² = 1.273240621 = tangent of the Pyramids angle of rise.
Circle
C (area) = 13,516.44286 "days" = area of the square
A1.
One side of the square
A1 =
116.2602377 days
Earth's equatorial diameter = 12.757.00336 (km):
(12.757.00336 : 10) - 465.1075454 =
810.5927906 = length of the Causeway (in meters):
"The total length of the causeway from the east face of the Great Pyramid to the site of the lower temple is not less than 810m"**
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*Ephemeris for the Sun: http://eclipse.gsfc.nasa.gov/TYPE/TYPE.html
**Length of the causeway: http://www.zahihawass.com/egyptian_hist_dev_khufu.htm